https://www.bannerkoubou.com/?fbclid=IwAR2BETNH2FFkIvVaFLbviLw1G0gRatAM3l_ihCfHrGyat0LmXWuhxHzcd68
https://www.bannerkoubou.com/?fbclid=IwAR2BETNH2FFkIvVaFLbviLw1G0gRatAM3l_ihCfHrGyat0LmXWuhxHzcd68
Expression:
These asset allocation percentage may not be exact due to rounding.
https://dplyr.tidyverse.org/reference/recode.html
My example:
court2qe$abc2<-recode(
court2qe$abc,"this is" = "X",
"That is" = "Y")
%let excelname=C:\Users....\xxx.xlsx;
PROC EXPORT DATA=_5_&num._result_&outcome OUTFILE= "&excelname"
DBMS=xlsx REPLACE;
sheet="&num.&outcome";
RUN;
Bank The one eyed dog without !
Tribute By Son To His Mother@ Her Home-going Service/ 50 Birthday Celebration. Amazing Grace!????
Posted by Bridgett Rayborn Crutchfield on Saturday, December 14, 2019
library(tidyverse)
my_list<-list(
c(1,2,6),
c(4,7,1),
c(9,1,5)
)
my_list[[1]] %>% mean()
my_list %>% map_dbl(mean)
map(my_list,mean)
my_list %>% map(~ . *1)
my_list %>% map(~ . *2)
pop<-rnorm(10000)
n<-1:1000
m1<-rep(NA,length(n))
for (i in n){
x<-sample(pop,i)
m1[i]<-mean(x)
}
plot(m1,type="l")
How do I count the number of cases with duplicative rows?
Example:
Name1 Name 2 x1 x2 x3
john smith 1 4 2
John smith 3 4 1
mary smith 4 2 4
ed wade 4 2 5
In this case the first two cases are duplicative rows.